Bayero University Kano(BUK) post UTME exam past questions and answers are now available in PDF for download. All the solutions have been checked and confirmed to avoid errors.

 You do not have to go to Bayero university to get past questions or wait for the exam date to start reading, as you know proper preparation prevents poor performance and SmartBukites is here to help you in your journey towards academic success.

These past questions are original copies obtained in Bayero University from legit sources and made available with answers to assist aspirants in preparing for their upcoming post-UTME screening examination. 

Did you pass the BUK jamb cut-off mark? Yes!  Congratulations you can now proceed to register for BUK post UTME.

Even with a high jamb score you still have to prepare for the post UTME screening examinations as it is calculated with your jamb score to get the aggregate score used to screen eligible candidates for admission.

Now is not the time to relent, you need to use the opportunity and prepare. Even with a 270-300 jamb score, a low post UTME score can reduce your chances of admission.

Did the pause in academic activities due to the ASUU strike stop you from reading? 

With the occurrence of COVID-19 which led to the lockdown in 2020 resulted in many universities merging jamb aspirants for admission which made gaining admission competitive and increased university expectations. 

Frequently studying past questions is an advantage to attaining academic excellence and also enables you to recognize similar or repeated questions.

In addition, just like jamb and every other exam is allocated time, the same goes for post UTME. Being familiar with Bayero University Kano post UTME exam past questions and answers can increase your ability to understand questions and accurately choose the correct answers.

Rather than be a victim of rewriting jamb, you can take a quick quiz on SmartBukites to test your readiness and download Bayero University Kano (BUK) post UTME past questions and answer for easy access whenever you want.

Subject Available

English

Read the following passage and answer the questions that follow

A wolf, seeing a lamb drinking from water, wanted to find a pretext for devouring him. He stood higher up the stream and accused the lamb of muddying the water so that he could not drink. The lamb said that he drank only with the tip of his tongue and that in any case he was standing lower down the river, and could not possibly disturb the water higher up. When this excused failed him, the wolf said: ‘well, last year you insulted my father.

‘I wasn’t even born then,’ replied the lamb. ‘You are good at finding answers,’ said the wolf, ‘but what do you mean by taking up so much of the path where I am walking?’ The lamb, frightened at the wolf’s angry tone and terrible aspect, told him, with all due submission, that he could not conceive how his walking on such a wide path could occasion him any inconvenience. ‘What!’ exclaimed the wolf, seemingly in great anger and indignation: ‘you are as impudent as your father who seized me by the throat last year, and caused me to be kept in a cage for three months.’

‘If you will believe me,’ said the lamb ‘my parents are poor simple creatures who live entirely by green stuff; we are none of us hunters of your species’. ‘Ah! I see it’s no use talking to you,’ said the wolf, drawing up close to him. ‘It runs in the blood of your family to hate us wolves and therefore as we have come so conveniently together, I’ll just pay off a few of your forefathers’ scores before we part.’ So saying, he leapt at the lamb from behind and garroted him.

The expression when this excused failed him suggests that the
a) Wolf only made up the charges levelled against the lamb.
b) Lamb was more intelligent than the wolf.
c) Lamb was prepared for the charges levelled against him.
d) Wolf was uncertain of the charges levelled against the lamb

a) Wolf only made up the charges levelled against the lamb.

The expression angry tone and terrible aspect refers to the wolf’s
a) Sonorous voice and overbearing attitude.
b) Towering size and thunderous voice.
c) Harsh and menacing posture.
d) Loud voice and fretting movement.

d) Loud voice and fretting movement.

Which of the following aptly describes the moral of the story?
a) The sins of the forefather are visited upon the children no matter how long it takes.
b) If you have made up your mind to hang your dog, any rope will do for the purpose.
c) The law is weak in defense of the poor against.
d) No matter how highly placed he is in society, the unmindful lawbreaker will always meet his nemesis.

b) If you have made up your mind to hang your dog, any rope will do for the purpose.

From the way the way the story ended, it can be concluded that the
a) Lamb did not survive the encounter.
b) Wolf and the lamb parted amicably.
c) Wolf had encountered the lamb’s parents.
d) Lamb offended the wolf quite seriously.

a) Lamb did not survive the encounter.

The charges levelled against the lamb are
a) greed, wandering, insolence and disrespect
b) exuberance, pollution, wickedness and stubbornness.
c) garrulity, loquacity, pride and arrogance.
d) pollution, insolence, obstruction and aggression.

b) exuberance, pollution, wickedness and stubbornness.

Use the right words to fill the sentences below :

Mrs. Jallow has just bought a…………………… bag. 

A. black new leather  B. new leather black 

C. leather black  D. new black leather.

A. black new leather 

He did it, but not ………………… in the way I had expected. 

A. as  B. quite
C. hardly  D. so.

B. quite

The driver……………. Nearly caused an accident.

A. rather B. almost 

C. very  D. quite.

B. almost 

Download PDF of BUK English Past Question and Solution (2008 -2020) »

Take English Aptitude Test Quiz »

Mathematics

Factorize 3a2 – 11a + 6
a) (3a – 2)(a – 3)
b) (2a – 2)(a – 3)
c) (3a – 2)(a + 3)
d) (3a + 2)(a – 3)
e) (2a – 3)(a + 2)

Multiply the coefficient of a2 and the constant term. Then find the factors of the product which when added or subtracted give the coefficient of the ‘a’ term.
This gives us factors of +18 which when added give -11 to be -9 and -2
3a2 – 9a – 2a + 6 = 3a(a – 3) – 2(a – 3)
(3a – 2)(a – 3)
Answer: [A]

In a bag of oranges, the ratio of the good ones to the bad ones is 5:4. If the number of bad oranges in the bag is 36, how many oranges are there altogether?
a) 81
b) 72
c) 54
d) 45
e) 49

The fraction of good oranges is 5/9 while the fraction of bad oranges is 4/9.
Let total oranges be represented by t such that
By making t subject of the formula, t = (36 x 9)/4 = 9 x 9 = 81
ANSWER: [A]

The equation can be rewritten as a2 – 3a – 10 = a2 – 5a + 2a – 10 = 0

a(a – 5) + 2(a – 5) = 0
(a – 5)(a + 2) = 0
Either a – 5 = 0 or a + 2 = 0
a = 5 or a = -2
ANSWER: [D]

The nth term of a sequence is represented by 3 x 2(2 – n). Write down the first three terms of the sequence.
a) 3/2, 3, 6
b) 6, 3, 3/2
c) 3/2, 3, 1/3
d) 2/3, 3, 8/3
e) 3/2, 0, 6

Given the formula 3 x 2(2 – n), all terms can be gotten by substituting for n.
First term, n = 1: 3 x 2(2 – 1) = 3 x 2 = 6
Second term, n = 2: 3 x 2(2 – 2) = 3 x 1 = 3
Third term, n = 3: 3 x 2(2 – 3) = 3 x ½ = 3/2
ANSWER: [B]

Evaluate 3.0 x 101 – 2.8 x 10-1, leaving answer I standard form.
a) 2 x 101
d) 2 x 102
c) 2.972 x 101
d) 2.972 x 102
e) 2.97 x 103

3.0 x 101 – 2.8 x 10-1 = 30 – 0.28 = 29.72
In standard form, 29.72 = 2.972 x 101
ANSWER: [C]

Evaluate ½ + ¾  of  2/5 ÷1 ⅗  
a) 15/16
b) 11/16
c) 49/50
d) 9(1/5)
d) 31/2

Using BODMAS: ½ + ¾  of  2/5  ÷1 ⅗  
= ½ + (¾  of  2/5) x  5/8
½ + (3/10 x 5/8)  =  ½ + 3/16 =  (8+3)/16 = 11/16 

ANSWER: [B]

p and q are two positive numbers such that p > 2q. Which of the following statements is true?
a) –p < -2q
b) –p > -2q
c) –q < -2p
d) q < 1/2p
e) p2 < 2q2

ANSWER: [A]
because among all the options, it is the only one that holds true. When inequality is multiplied or divided through by a negative number, the sign of the inequality gets reversed.

A piece of cloth was measured as 6.10m. if the actual length of the cloth is 6.35m, find the percentage error correct to 2 decimal places.
a) 30.50%
d) 3.94%
c) 15.00%
d) 25.00%
e) 39.30%

Fractional error = Error/(Correct length)
Error = Difference in measurements = 6.35 – 6.10 = 0.25
Percentage error = Fractional error x 100% = 0.25/6.35  x 100% = 3.94%
ANSWER: [B]

A trader makes a loss of 15% when selling an article. Find the ratio of the selling price to the cost price.
a) 3:20
b) 17:20
c) 3:17
d) 20:23

At a loss of 15 percent, the selling price is 0.85 (1 – 0.15) of the cost price, giving a ratio of 0.85:100 which when reduced becomes 17:20.
ANSWER: [B]

Make S subject of the formula in V = K/(√(T-S))
a) S = T – (K/V)2
b) S = (K/V)2 – T
c) S = T – (V/K)2
d) S = (T(V2 – K2))/V2
e) S = T + (K/V)2

By cross-multiplying, V√(T-S) = k is gotten
Square both sides: V2(T – S) = K2
Divide both sides by V2: T – S = K2/V2
By switching places: S = T –  K2/V2
ANSWER: [A]

Take Mathematics Aptitude Test Quiz »

Physics

In order for the error of parallax when taking measurements with a meter rule, the eye should be focused
a) Slantingly towards the left of the markings
b) Slantingly towards the right of the markings
c) Vertically downwards on the markings
d) Vertically Upwards on the markings.

THE CORRECT ANSWER IS C: THAT IS TO LOOK AT THE READINGS STRAIGHT DOWNWARD WITHOUT SLANTING, ELSE ANOTHER READING WILL BE VIEWED.

A load is pulled at a uniform speed along the horizontal floor by a rope at 450 to the floor. If the force in the rope is 1500N, what is the frictional force on the load?

Velocity Time Graph

a) 1524N

b) 1350N

c) 1260N

d) 1061N

F= mgCOSθ
mg= 1500N       and θ= 450
F= 1500 (cos 450) = 1500 (0.7071) = 1060.66N

ANSWER D

From the Velocity time graph shown above, which of the following quantities CANNOT be determined?

a) Deceleration

b) Initial Velocity

c) Total Distance travelled

d) Initial acceleration

Deceleration, Initial velocity(60m/s) and total distance travelled can all be found from the diagram above, but we can’t find Initial acceleration. ANSWER : D

A rocket is fired from the earth’s surface to a distant planet. By Newton’s law of universal gravitation, the force F will
a) increase as r reduces
b) increase as G varies
c) remains constant
d) increases as r increases.

From the Newton’s law of universal gravitation, the Force (F) is Inversely proportional to distance (r), This shows that as the Force will increase as the distance reduces. ANSWER : A

An object moves in a circular path of radius 0.5m with a speed of 1ms‑1. What is its angular velocity?

a) 8 rads-1

b) 4 rads-1

c) 2 rads-1

d) 1 rads-1

radius(r) = 0.5m and speed(v)= 1ms-1, Angular velocity
ω = v/r
ω =  1/0.5 = 2rads-1 ANSWER C

From the diagram, calculate the work done when the particle moves from x = 0m to x = 80m.


a) 1200J
b) 2400J
c) 6000J
d) 7000J

Work done= Force x Distance =The Area.
From x = 0m to x=80 m= Area of (ΔABC + ΔBDC + ΔEEF)
RECALL; AREA OF TRIANGLE = ½ BASE*HEIGHT
= ½ (AC*BC) + ½ (CD*BC) + ½ (DF*FE)
= ½ [(30*80) + (40*80) + (20*(-40))]
= ½ (2400 + 3200 – 800)    =>    = ½ (4800)
= 2400J ANSWER B

A pinhole camera is placed 300m in front of a building so that image is formed on a screen 5cm from the pinhole. If the image is 2.5cm high, the height of the building will be
a) 25m
b) 50m
c) 100m
d) 150m

v/u = hi/h0   =>       

2.5/5 = hi/300    =>  300(0.5) = 150m  
ANSWER D

After the reflection from the concave mirror, rays of light from the sun converge.
a) At the radius of the curvature
b) At the focus
c) Beyond the radius of curvature
d) Between the focus and radius of curvature

Rays of light parallel to the principal axis of a concave mirror will appear to converge on a point in front of the mirror somewhere between the mirror’s pole and its centre of curvature. That makes this a converging mirror and the point where the rays converge is called the focal point or Focus.
ANSWER B

Dispersion of white light is the ability of white light to
a) Penetrate air, water and glass
b) Moe in a straight line
c) Move around corners
d) Separate to its component colours

Visible light, also known as white light, consists of a collection of component colours. The white light is separated into its component colours (red, orange, yellow, green, blue & violet). The separation of visible light into its different colours is known as Dispersion. ANSWER D

A piece of radioactive material contains 1000 atoms. If its half-life is 20 seconds, the time taken for 125 atoms to remain is
a) 20 seconds
b) 40 seconds
c) 60 seconds
d) 80 seconds

A piece of radioactive material contains 1000 atoms. If its half-life is 20 seconds, the time taken for 125 atoms to rN = N0 e-λt  
N = 125,    N0=1000,    λ=0.693/T where T is given as 20seconds
λ = 0.693/20 = 0.03465
:. 125 = 1000e-0.03465t
1000/125= e0.03465t = 8            (Recall; If a=eb, then b=Lna)
Ln8= 0.03465t = 2.0794
:. t =  2.0794/0.03465= 60.
        Therefore: t = 60 Seconds. ANSWER: C

Download PDF of BUK Physics Past Question and Solution(2008 – 2020) »

Physics, Chemistry and Biology Quiz-BUKAT

Chemistry

Which of the following indicate the correct increasing order of oxidizing power of the halogens?
A) F>CI<Br<I
B) I< Br<Cl<F
C) I<Cl<Br<F

D) Cl<F<I<Br

(B)
Halogen family are very good oxidizing agents with flourine being the strongest oxidizing agent and
iodine as the least oxidizing agent.
Increasing order of oxidizing power: I<Br<Cl<F.

What is the major product formed when C2H5OH reacts with ethanoic acid?
A) C2H5COOCH3
B) C2H5COCH3
C) CH3COOC2H5
D) C3H2COOH

(C)
C2H5OH + CH3COOH ====> CH3COOC2H5 + H2O
This is an esterification reaction.

What is the oxidation number of chromium in K2CrO4
A) +1
B) +2
C) +4
D) +6

(D)
The oxidation number of chromium is calculated as shown below;
Oxidation number of K= +1
Oxidation number of O= -2
K2CrO4===> 2(+1) + Cr + 4(-2)= 0
+2 + Cr -8 = 0
Cr= +8 – 2
Cr= +6

What volume of carbon (II) oxide is produced by reacting excess carbon with 10dm3 of oxygen?
a) 15dm3
b) 10 dm3
c) 5 dm3
­­d) 20 dm3

2 vol. of carbon reacts with 1 vol. of oxygen to produce 2 vol. of Carbon (II) oxide

2C + O2   à 2CO
2    :  1   :       2
1dm3 of O2  = 2dm3 of CO
10dm3 of O2 = Xdm3 of CO
By Cross Multiplying: X = 20dm3 of CO. ANSWER D

The rate of diffusion of Y is twice that of Z. If the relative molecular mass of Y is 64 and the two gases diffuse under the same conditions. Find the relative molecular mass of Z
a) 8
b) 16
c) 32
d) 256

Let the rate of diffusion of Y be r1 and that of Z be r2,
Relative Molar masses of Y and Z be M1 and M2 respectively
Given that r1 = 2r2, and M1 = 64, M2 = ?
From Grahams law of Diffusion,
r2/r1 =√(M1/M2 )     But r1 = 2r2, so , r2/2r2 =√(64/M2 )         
(½ )2=  64/M2            ¼ M2 = 64     :. M2 = 64 x 4 =  256.
ANSWER D

How many unpaired electrons are there in the P-orbitals of fluorine?
a) 1
b) 2
c) 3
d) 0

Fluorine(F) has 9 electrons and Electronic Configuration of  1s22s2 2p5 

Since P-orbital takes the maximum of Six Electrons, Fluorine has 1 unpaired Electron. ANSWER A

Which of the following molecule is held together by hydrogen bond?
a) H2SO4
b) HF
c) CH4
d) HBr

A Hydrogen Bond is an intermolecular force that forms a special type of dipole-dipole attraction when a hydrogen atom bonded to a strongly electronegative atom bonded to a strongly electronegative atom exists in the vicinity of another electronegative atom with a lone pair of electrons. In the HF, electrons are displaced toward the more electronegative fluorine atom. ANSWER B

The bond formed between two elements having electronic configurations 1s22s22p63s2 and 1s22s22p4 is
a) Dative
b) Ionic
c) Metallic
d) Covalent

1s22s22p63s2 is the Electronic Configuration of Magnesium (Mg) and 1s22s22p4 is the Electronic Configuration of Oxygen (O). Mg loses two electrons to have an octet, and oxygen gains two electrons to have an octet. The IONIC bond between ions results from the electrostatic attraction of opposite charges. The final formula of Magnesium Oxide is MgO.
ANSWER B

In an electrochemical cell, polarization is caused by
a) Tetraoxosulphate (IV) acid
b) Hydrogen
c) Chlorine
d) Oxygen

Polarization is a deviation of the electrochemical process from equilibrium due to an electric current passing through the galvanic cell. If aqueous is used, hydrogen ions are converted to hydrogen atoms and H2 molecules, at extreme conditions, bubbles of hydrogen gas appear at one of the electrodes. An electrode covered in gases is said to polarized.
ANSWER B

The minimum amount of energy required for a reaction to take place is
a) Activation energy
b) Kinetic Energy
c) Lattice energy
d) Ionization energy

Activation Energy is the minimum amount of energy required to cause a process (such as Chemical Reaction)to occur.
ANSWER A

Download PDF of BUK Chemistry Past Question and Solution (2008 – 2020) »

Physics, Chemistry and Biology Quiz-BUKAT

Biology

1. A plant which grows on another plant without apparent harm to the host plant is
called?
A. a parasite
B. An epiphyte
C. Saprophyte
D. Predator.

(D) PREDATOR

The process in which complex substances are broken down into simpler ones is referred to as
a) Metabolism
b) Tropism
c) Anabolism
d) Catabolism

Catabolism is the set of metabolic pathways that breaks down large molecules into smaller units that are either oxidized to release energy or used in other anabolic reactions.
ANSWER D

2. Which of the following is not an excretory organ?
A. Lungs
B. kidney
C. Skin
D. large intestine

(C) SKIN

 The deficiency of vitamin D leads to
A. Scurvy
B. pellagra
C. Rickets
D. beriberi.

( A )
Liverworts and mosses undergo alternation of generations.

The organ which is sensitive to light in Euglena is the
a) Chloroplast
b) Eyespot
c) Gullet
d) Flagellum

The eyespot in Euglena is an organ that allows the cells to sense light direction and intensity and respond to it, prompting the organism to either swim towards the light (positive phototaxis), or away from it (negative phototaxis).
ANSWER B

The organelles present in the cells that are actively respiring and photosynthesizing are
a) Nucleus and centrioles
b) Mitochondria and chloroplast
c) Lysosomes and ribosomes
d) Golgi apparatus and endoplasmic reticulum

The process of photosynthesis starts when light is trapped by the green pigment called chlorophyll present in the chloroplasts.
Cellular respiration involves the processes of breaking down food particles to release energy which occurs within the mitochondria
ANSWER B

Which of the following describes a characteristic of anthropods?
a) The body is covered by chitin
b) The body is not divided into a number of segments
c) The organism finds it easy to grow freely
d) The organism has a pair of jointed appendages

Arthropods are a lineage of life that developed skeletons on the outside – their hard shells, made of a material called “chitin” – instead of on the inside for structural support
ANSWER B

Which of the following distinguishes a butterfly from a moth?
a) They have similar antennae
b) The abdomen of a moth is fatter than that of butterfly
c) The wings of butterfly rest horizontally but those of moth rest vertically
d) Both are active during the day

Butterflies tend to fold their wings vertically up over their backs. Moths tend to hold their wings in a tent-like fashion that hides the abdomen.
Butterflies typically has larger(fatter) abdomen. Moths has smaller abdomen
Both B and C can be the answer

The plants that grow in deserts or very dry areas are referred to as
a) Epiphytes
b) Xerophytes
c) Mesophytes
d) Hydrophytes

Plants that have adapted for growth in deserts or arid environments are called xerophytes.
Xerophytes have developed special adaptations suited to the harsh environment of deserts and similar areas
ANSWER B

The blood circulatory system of vertebrates consists of
a) Heart, aorta, arteries and veins
b) Heart, vena cava, arteries and veins
c) Heart, arteries, capillaries and veins
d) Heart, aorta, capillaries and veins

The primary function of a heart is to pump blood to the entire body which goes through arteries, send to the entire body through capillaries and then collected back to the heart through veins for another circulation.
ANSWER C

Download PDF of BUK Biology Past Question and Solution(2008 -2020) »

Physics, Chemistry and Biology Quiz-BUKAT

BUK Post UTME Past question and solution: